Question

an electric lamp whose resistance is 40 ohm and conductor of 8,ohm resistance are connected in series to 12v battery in an electric circuit calculate the total resistance of the circuit and the current flowing through the circuit
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Answer 1

Given : An electric lamp whose resistance is 40 ohm and conductor of 8 ohm resistance are connected in series to 12v battery.

To find : The total resistance of the circuit and the current flowing through the circuit.

Solution :

The total resistance is 48 Ω and 0.25A current is flowing through the circuit.

We can simply solve this numerical problem by using the following process. (our goal is to calculate the total resistance of the circuit and the current flowing through the circuit)

As the connection is in series, so the total resistance will be :

Total resistance = Resistance of lamp + Resistance of conductor = (40+8) = 48 Ω

Now, we know that :

V = IR

(V = Voltage , I = Current , R = Resistance)

By, putting the available values, in the above-mentioned mathematical equation, we get :

12 = I × 48

I = 12/48

I = 0.25 A

Hence, the total resistance is 48Ω and 0.25A current is flowing through the circuit.

Answer 2

Answer:

the above answer is correct