Question

An electric lamp whose resistance is 40 ohm and conductor of 8ohm resistance are connected in series to 12V battery in an electric circuit. Calculate the total resistance of the circuit and the current flowing through the circuit.
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Answer 1

answer:

lamp resistance- 40

conductor resistance- 8

total resistance- 40+8=48

Answer 2

Total resistance is 48ohm and the current is 0.25A

Step-by-step Explanation:

Given: Resistance of the lamp R₁ = 40ohm

Resistance of the wire R₂ = 8ohm

Voltage V = 12V

To Find: Total resistance and current

Solution:

• Finding Resistance

Since the resistance R₁ and R₂ are in series, we have

R(eq) = R₁ + R₂

⇒ R(eq) = 40 + 8 = 48ohm

⇒ R(eq) = 48ohm

• Finding Current

According to the ohm's law,

V = I(eq) × R(eq)

⇒ 12 = I(eq) × 48

⇒  I(eq) = 12/48 = 0.25A

⇒  I(eq) = 0.25A

Hence, the total resistance is 48ohm and the current is 0.25A