Question

an electric lamp whose resistance is 6 ohm and a conductor of resistance 4 ohm are connected to a 6 V battery . calculate the resistance find the total current flowing in circuit.



please help ​

Answer 1

Given:-

• Resistance of Electrical lamp ,R1 = 6 ohm

• Resistance of Conductor ,R2 = 4 ohm

• Potential Difference ,V = 6 v

To Find:-

• Total Resistance ,R
• Total Current ,I

Solution:-

If the Lamp and Resistor are connected in series . Then Equivalent resistance is equal to Sum of individual resistance of each Resistors.

• Req. = R1 + R2

Substitute the value we get

→ Req = 6+ 4

→ Req = 10 ohm

Therefore, Total Resistance is 10 ohms.

Now, We have to calculate the total electric current .So, Using Ohm's Law

• V = IR

Where,

V is the Potential Difference

I the electric current

R is the Resistance

Substitute the value we get

→ 6 = I × 10

→ I = 6/10

→ I = 0.6 A

Therefore,the total current flowing through the circuit is 0.6 Ampere.

Answer 2

Answer:

Given :-

• Resistance of electrical lamp = 6 ohm
• Resistance of conductor = 4 ohm
• Power of battery = 6 Volt

To Find :-

1. Resistance
2. Total current

Solution :-

❶ Total Resistance

As they are connected to same battery, therefore.

$\sf Req = R1 + R2$

$\sf \: Req = 6 + 4$

$\sf Req \: = 10 \: ohm$

Therefore total resistance = 10 ohm

❷ Total Current

As we know that potential difference is defined as the product of current and resistance.

Therefore,

$\huge \fbox {V = IR}$

Here,

V = Potential difference

I = Current

R = Resistance

$\sf \: 6 = i \times 10$

$\sf \: i = \dfrac{6}{10}$

$\huge \bf \therefore \: Current \: = 0.6 \: A$