Question

An electric lamp whose resistance is 8 ohms and a conductor of 2 ohms resistance are
connected in series to a 5 volt battery. Calculate
A. The total resistance of the circuit
B. The current through the circuit
C. The potential difference across the electric lamp and the conductor
​

Answer 1

Explanation:

In series combination,

R=R

Lamp

+R

conductor

=10Ω+2Ω=12Ω

I=

R

V

=

12Ω

6v

=0.5A

⇒V

Lamp

=IR=0.5×10=5V

solution