Question

an electric lamp whose whose resistance is 20 ohm and a conductor pf 4 ohm resistance is connected to 6v. battery calculate potential difference across the lamp and conductor​

Answer 1

Answer:

Potential difference across the electric lamp, V1 = IR1 = 0.25 A x 20 Ω = 5 V. Potential difference across the conductor is, V2 = IR2 = 0.25 A x 4 Ω = 1 V.