Question

An electric light fixtures weighting 15 N hangs from a point C by two strings AC and BC the strings AC is inclined at 60degree to the horizontal and BC at 45 degree to the horizontal as shown in figure determine the forces in strings AC and BC

Answer 1

Answer:

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Answer 2

Take any half of triangle

sinx=p/h

sin45=15/h

h=15/sin45

h=15/0.707106

h=21.213

Another half

sin60=15/K

k=15/0.8660

k=17.32