Question

An electric lmao whose resistance is 30 ohm and a conductor of 6 ohm resistance are connected to a 6V battery. Calculate a)the total resistance of the circuit b)the current through the circuit​

Answer 1

Answer:

a) 36 0hm

b) 1/6 ampere

Explanation:

since electric Imao and conductor are connected in series

therefore,

R = R¹ + R²

R = (30+6) ohm

R = 36 ohm

Now,

Since V = IR

I = V/R

I = 6/36 (V=6V ,given)

I = 1/6 ampere