An electric motor can lift up the 1000 kg of water to a height of 45 meter in 5.5 minutes.The efficiency of the motor is 50%.What will be the changing spent energy of the machine, when its efficiency increases by 10%.Analyse mathematically.
Answers
Answer:
Answer:
\boxed{\mathfrak{(b) \ 50\%}}
(b) 50%
Given:
Input Power (\sf P_iP
i
)= 100 W
Mass (m) = 10 kg
Height (h) = 10 m
Time (t) = 20 s
To Find:
Efficiency of the motor
Explanation:
\star⋆ Output power of the motor:
\boxed{ \bold{Out put \: power \: (P_o)= \frac{mgh}{t}}}
Outputpower(P
o
)=
t
mgh
\begin{gathered}\sf \implies P_o = \frac{10 \times 10 \times 10}{20} \\ \\ \sf \implies P_o = \frac{1000}{20} \\ \\ \sf \implies P_o = \frac{ \cancel{20} \times 50}{ \cancel{20}} \\ \\ \sf \implies P_o = 50 \: W\end{gathered}
⟹P
o
=
20
10×10×10
⟹P
o
=
20
1000
⟹P
o
=
20
20
×50
⟹P
o
=50W
\star⋆ Efficiency of the motor:
\boxed{ \bold{Efficiency = \frac{Out put \ Power \ (P_o)}{In put \ Power \ (P_i)} \times 100}}
Efficiency=
Input Power (P
i
)
Output Power (P
o
)
×100
\begin{gathered}\sf \implies Efficiency = \frac{50}{ \cancel{100}} \times \cancel{100} \\ \\ \sf \implies Efficiency = 50 \: \%\end{gathered}
⟹Efficiency=
100
50
×
100
⟹Efficiency=50%
\therefore∴
Efficiency of the motor = 50 %
hope it helps!!
Answer:
10,000
Explanation:
1000kg *10
*7=(=889=*55567)