Question

An electric motor has a back e.m.f. of 110V and armature current of 90A. The armature is making 2.5 rps. Then find the power developed and torque on the armature.

Answer 1

Answer:

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Answer 2

Explanation:

P=VI

given,

V=110V,

I=90A

⇒P=110×90

∴P=9900 Watt

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