an electric motor is so operated that works for 100s and 80% efficient. if the power is 1500w, calculate (1)useful work done by the motor (2)load lifted by it through a height of 10 m.
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Efficient power used is 80%
so, 80% of 1500w = 1200 w
useful work done = p x t
= 1200 x 100
= 120000 J
= 120 KJ
(2) is load is mass
1500 = 10 x 10 x mass x efficiency / time
15 = mass x 1200 / 100
5/4 = mass
so, 80% of 1500w = 1200 w
useful work done = p x t
= 1200 x 100
= 120000 J
= 120 KJ
(2) is load is mass
1500 = 10 x 10 x mass x efficiency / time
15 = mass x 1200 / 100
5/4 = mass
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