Question

An electric motor is used to lift a mass of 2.5kg to a height of 7.5m in 1.5s. Calculate the gain in GPE and power of the motor. How much of work is done?

Answer 1

Answer:

Power is 125 W

Work Done is 185.5 J

Explanation:

m= 2.5 kg

g= 10m/s^2

h= 7.5 m

P = W/t

=P.E/t

=mgh/t

( Put the given values )

W = F.S

= mg . h

( Put the given values )

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