Question

An electric motor lifts a 8 kg box vertically through 2.5 m in 10s. The power produced by the motor is:​

Answer 1

m = 8kg , h = 2.5 m , t = 10s ....

let s" represent power

s" = work /t = FSCosø /t = mg S cosø /t

= {8 * 10 * 2.5 * cos 0 / 10 } W

= {20 * cos 0}W = 20W ........

hope it helps. ..............

Answer 2

Answer:

The power produced by the motor is 20 watts.

Explanation:

The power produced by the motor is calculated as,

$P=\frac{mgh}{t}$     (1)

Where,

P=power produced by the motor

m=mass of the body

g=acceleration due to gravity=10m/s²

h=height to which the body is raised

t=time in which the body is raised

From the question we have,

The mass of the box=8 kg

The height to which the box is raised=2.5

The time used for this =10 seconds

We get the following results by plugging in all of the relevant values into equation (1):

$P=\frac{8\times 10\times 2.5}{10}$

$P=20\ watts$

Hence, the power produced by the motor is 20 watts.

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