Question

An electric motor of 1.0kw operates at 220v for 6 hours daily. What is the current drawn by the motor? What is the cost of running the motor for 30 days if the rate of electric energy is 50 paisa per unit?
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Answer 1

Rate at which electric energy is consumed dissipated in an electric circuit .

E = p × t × no. of days = 2kw × 2h × 30 = 120

kWh = 120 unit

∴ Cost = 6 × 120 = 720.

Answer 2

Solution :-

As per the given data ,

• Power (P) = 1 Kw
• Voltage (V) = 220 V
• Time = 6 hrs (daily)

As per the formula ,

➜   P = VI

➜   I = P / V

➜   I = 1000  / 220

➜   I = 4.54 A

The current drawn by the motor is 4.54 A

Per day  energy consumption = 1 kW x 6 = 6 KWh

Monthly energy consumption = 6 kWh x 30 = 180 KWh

Rate = 50 paisa / unit

➜  Total cost = 180 x 50

➜  Total cost =9,000 paisa

We know that ,

➜  1 rupee = 100 paisa

➜  Hence ,

➜  9,000 paisa = 90 rupee

Total cost of running the motor for 30 days is ₹ 90