Question

an electric motor of power 100 mw is used to drive the stirrer in water bath. If 40% OF energy supplied to the motor is spent in stirring the water,then the work done on water in one minute​

Answer 1

Answer:

Power supplied=100W, time t=60s

So, power used in stirring water = 50% of the power supplied=

100

50

×100W=50W

Work done on water = power used × time =50W×60s=3000J

Answer 2

$\huge\mathbb\red{SOLUTION}$

$\orange{▬▬▬▬▬▬▬✯✯✯▬▬▬▬▬▬▬}$

ɢɪᴠᴇɴ,

✦ Pᴏᴡᴇʀ Sᴜᴘᴘʟɪᴇᴅ = 100 W ,

✦ Tɪᴍᴇ (t) = 1 minute = 60 s

✫Power used in stirring the water

➞ 40 % of the power supplied

$➞\frac{40}{100} \times 100W$

$➞ 40W$

✫ Work done on water

:↦Power used × Time

:↦40 W × 60 s

:↦2400 J

$\orange{▬▬▬▬▬▬▬✯✯✯▬▬▬▬▬▬▬}$