Question

An electric motor of Power 100 W is used to drive the stirrer in a water bath. lf 50 % of the energy supplied to the motor is spent in stirring the water, calculate the work done on water in 1 minute ?​

Answer 1

Step-by-step explanation:

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Given,

Power Supplied = 100 W

Time = 1 minute = 60 seconds

Now,

Power used in stirring the water :-

= 50 % of the power supplied

= $\frac{50}{100} \times 100 \: W \ \ = 50 \: W$

Then,

Work done on Water :-

= Power used × time

= 50 W × 60 S

= 3000 J

Therefore,

The work done on water in 1 minute

= 3000 Joule.

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Answer 2

Answer:

An Electric motor :

Power (P) = 100 watt.

Time(t) = 1 minute = 60 seconds.

∴ Work done by motor = Produced energy

P x t = 100 x 60 = 6000 Joule.

∴ Work done on water by motor = 50% of total produced energy 

= 50/100 x 6000 = 3000 Joule.