Question

An electric motor of power 3 kW is to be operated at mains of 220 V. Find the current

rating of the fuse to be connected with the motor.​

Answer 1

Answer:

Given,

Power=2kw=2000W,current=5A,voltage=220V

So power=current×voltage⇒current=

voltage

power

⇒

220

2000

=9A

Thus the current will exceeds and the fuse will burn out if there is no fuse then overloading will cause melting of wires which will cause the short circuit which will cause a fire.