Question

An electric motor of power 3kW is to be operated at mains of 220V.Find current rating of fuse to be connected with motor.​

Answer 1

Answer:

P=VI

Explanation:

3000=220×I

3000/220=13.63

Answer 2

The current rating of the motor is 13.63 A.

Explanation:

Given that,

Power of electric motor, P = 3 kW = 3000 W

Voltage, V = 220 volt

The electric power of an electrical appliance is given by the product of voltage and current. It is given by :

$P=V\times I\\\\I=\dfrac{P}{V}\\\\I=\dfrac{3000\ W}{220\ V}\\\\I=13.63\ A$

So, the current rating of the motor is 13.63 A. Hence, this is the required solution.

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