Question

an electric motor of power rating 300w is used to drive the stirrer in a water bath if 50%of energy supplied to the motor is spent in string the water than the work done on the water in 25 min​

Answer 1

Answer:

225000 Joules

Explanation:

50% energy is supplied to water for stirring work so let's find the total energy generated by the motor.

power is the rate of work done

so

E=p*t

p=300watts

and t = 25 min= 25*60=1500sec

E=300*1500

E=450000joules

now 50% of this energy is

e= 225000 joules

which is the amount of work done on water

so E=