An electric motor on the ground floor of a building can pump up water to fill
a tank of volume 30 m3 in 15 min. If the tank is 40 m above the ground and
efficiency of the electric motor is 30%, how much electric power is consumed
by the motor ? The density of water is 1000 kgm-3.
Answers
electric power is consumed by the motor is 44444.4 watt.
[ note : answer may vary because I have used g = 10m/s² . you didn't mention about it. if answer is different then please use g = 9.8 m/s² you will get the accurate answer ]
volume of water in the tank = 30 m³
so, mass of water , m = volume × density
= 30m³ × 1000 kg/m³
= 30,000 kg
height of tank from the ground, h = 40m
so, potential energy of water , U = mgh
= 30,000 kg × 10m/s² × 40
= 12 × 10^6 J
power required for pumping = potential energy/time taken
= 12 × 10^6 J/15 × 60 sec
= (1/75) × 10^6 watt
30 % of electric power is consumed by the motor = power required for pumping
⇒electric power is consumed = (1/75) × 10^6 × 100/30
= 0.0444444 × 10^6 watt
= 44444.4 watt
also read similar questions : A pump on the ground floor of a building can pump up water to fill a tank of volume 30 m3 in 15 min. If th...
https://brainly.in/question/1382764
What is power, work and energy?
https://brainly.in/question/11737596