Question

An electric motor operating on 50 V DC supply draw a current of 12 A is the efficiency of motor is 30% then resistance of the winding
of the motor

Answer 1

Answer:

Solution :

given V=50V

I=12A

n=30%

Input power = VI

=50×12=600walt

Since n=30% , the energy dissipated as heat

P=70100

=70100×600

=420w

P=I2R

R=PI2

=42012×12

=2.9Ω

or 3Ω (approx)