An electric motor raises a load of 0.2 kg, at a constant speed, through a vertical distance of 3.0m in 2s. If the acceleration of free fall is 10m/s^2, the power in watt developed by the motor in raising the load is
Answers
Answered by
9
Answer:
An electric motor raises a load of 0.2 kg, at a constant speed, through a vertical distance of 3.0m in 2s. If the acceleration of free fall is 10m/s^2, the power in watt developed by the motor in raising the load is 3.0
Answered by
26
Answer:
hiiiiii
your answer is here !
Explanation:
=> MASS = 0.2 kg
=> HEIGHT = 3 m
=> GRAVITY = 10 m/s
=> TIME = 2 sec
=> POWER = MASS * GRAVITY * HEIGHT / TIME
= O.2 * 10 * 3 / 2
= 6 / 2
= 3 WATTS
=> S.I UNIT OF POWER IS WATT
follow me !
Similar questions