An electric oven consumes 1Kw electric power when operated 220V.Write the capacity of the fuse suitable for your device.Give reason for your answer.
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Answers
Answered by
2
Given Value
p=1000watt
V=220v
then p=v*I
I=p/v
I=1000/220
=4.54A
then the fuse should be of 5A.
p=1000watt
V=220v
then p=v*I
I=p/v
I=1000/220
=4.54A
then the fuse should be of 5A.
Answered by
11
Given :- P = 1 kw = 1000w; V = 220 V
To Find :- Capacity of the fuse i.e. I(current)
As according to the formula,
P= V×I
I = P/V
I = 1000/220
I = 4.545 A
Thus, the capacity of fuse is of 4.54 A.
This shows that fuse only passes the current according to the nature of more current will pass then fuse will melt and no current will pass through the circuit.
To Find :- Capacity of the fuse i.e. I(current)
As according to the formula,
P= V×I
I = P/V
I = 1000/220
I = 4.545 A
Thus, the capacity of fuse is of 4.54 A.
This shows that fuse only passes the current according to the nature of more current will pass then fuse will melt and no current will pass through the circuit.
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