Question

An electric oven of 1.5 kW is operated in a domestic circit (220 V) hat has a current rating of 5 A .What result do you expect in this case ? Explain

Answer 1

Answer:

Current drawn by the electric oven can be obtained by the expression,

P = VI

I= P/V

Where,

Current = I

Power of the oven, P = 1.5 kW = 1500 W

Voltage supplied, V = 220 V

I = 1500 / 220

I = 6.818 A

Hence, the current drawn by the electric oven is 6.818 A, which exceeds the safe limit of the circuit. Fuse element of the electric fuse will melt and break the circuit.

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Answer 2

The result expected in this case is short circuit.

Given - Power, voltage and current rating

Find - Result on operating electric oven

Solution - Firstly we will calculate the current requirement of electric oven. Accordingly, the result on operating electric oven will be state.

Current requirement will be calculated by the formula -

P = V×I, where P is power, V is Voltage and I is current.

Converting Power to Watt. We know -

1 kW = 1000 W

So, 1.5 kW = 1000 × 1.5

1.5 kW = 1500 W

Now, keep the values in formula to find the value of current.

I = $\frac{1500}{220}$

I = 6.8 Amperes.

We can see that electric oven requires 6.8 Amperes of current. But, the current rating of circuit is only 5 Ampere. On using electric oven, excess current will flow into the circuit. This will result in melting the fuse and hence circuit will break.

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