Question

An electric oven of 2 kW is operated in a domestic electric circuit (220 V) that has a current rating of 5 A. What results do you expect? Explain.





Phirends? ​

Answer 1

Given,

Power=2kw=2000W,current=5A,voltage=220V

So power=current×voltage⇒current=

voltage

power

⇒

220

2000

=9A

Thus the current will exceeds and the fuse will burn out if there is no fuse then overloading will cause melting of wires which will cause the short circuit which will cause a fire.

Answer 2

Answer:

Explanation:

Power=2kw=2000W,

current=5A,

voltage=220V

So power=current×voltage

⇒ current=  voltage /power

​ 220 /2000 =9A

​ Thus the current will increase and the fuse will burn out, if there is no fuse which will cause the short circuit which will lead to accidential fire.