Question

An electric oven of 2 kW power rating is operated in a domestic electric circuit (220 V) that has a current rating of 5 A.
a) what is the current drawn
b) what will happen to the fuse

Answer 1

Answer:

A) 9.09A. B) fuse will melt due to high flow of current than the capacity of the fuse

Explanation:

A) GIVEN,

Power(P) = 2kW =2000W

The fuse capacity =5A

We know that,

P=Vi

By substuting the values we get,

2000 = (220)i

i=2000/220

i =9.09A

B) Therefore the current drawn is grater than the capacity of fuse that's why the fuse melts

Answer 2

Answer:

• The rated current for 2KW, 230V electric oven is as follows, ( 230V is the standard 1-phase voltage in India)

• P = VI

• ⇒I=P/V ( Assuming PF=1)

• = 2000/200

• = 20

When the oven is connected to 5A, 220V circuit,

• - it draws more current than it is rated for (2000/220 = 9.1A approx) hence may heat up beyond safe limit.

• - the wires of the circuit to which it's connected heats up and may melt due to over heating.
• - the socket terminals heat up or even melt down due to over heating.

• If the oven is operated for long time in such circuit, it may damage the oven coil and also could damage the switch and socket permanently.

• Further, since the switch and socket are under rated there insulation may fail and cause electric shock to the preson operating it.

• Some times the pin of the plug also gets welded with the socket metal due to over heating and doesn't get unplugged.

$hope \: its \: help \: u$