An electric oven of 2 kW power rating is operated in a domestic electric circuit (220 V) that has a current rating of 5 A. What result do you expect? Explain.
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The power rating of electric over is given as 2 kW.
The voltage of domestic electric circuit is 220V. The current rating is 5 A.
The value of power is V×I.
2kW = 220 × I
I = 2000/220
I = 9.09 A
When the rate of current flowing in a conductor is higher than 5 A of current, then the fuse will completely get broken and therefore the circuit will open.
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Explanation:
Current drawn by the electric oven can be obtained by the expression,
P = VI
Where,
Current = I
Power of the oven, P = 2 kW = 2000 W
Voltage supplied, V = 220 V
I = 2000/220 V = 9.09 A
Hence, the current drawn by the electric oven is 9.09 A, which exceeds the safe limit of the circuit. Fuse element of the electric fuse will melt and break the circuit.
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