An electric oven of 2kw is operated in a domestic electric circuit (220v) that has a current rating of 5A. What result do you expect? Expalin
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Answer:
Fuse wire will break.
Explanation:
Power is given by :-
P=VI
=> I=P/V
For the current scenario, P=2kW= 2000W and V=220V
Hence, I=2000/220 = 200/22 = 9.09A
This shows that the oven draws a current of 9.09 A whereas the fuse has a limit of 5A. Due to the excess current, the fuse will melt.
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