Question

an electric oven of 2kw power rating is operated in a domestic electric circuit 220 volt that has a current rating of 5 A.What result do you expect?Explain​

Answer 1

Answer:

In this problem we have

Power of the oven (P) = 2 kW = 2000 W

Potential Difference (V) = 220 V

We have P = VI

⇒I=P/V

= 2000/220

= 9.09A

Here the current drawn by the electric oven is 9.09 A, which exceeds the safe limit of the circuit that is 5A. Therefore electric fuse will melt and break the circuit.

Explanation:

Answer 2

Answer:

P = 2KW = 2000KWH

P.D = 220 V

P = VI

2000 = 220 x I

I = 2000 ÷ 220  =  9.09A

Since the electric oven can only accept a maximum of 5A current flowing through it, the fuse wire melts and the electric oven gets damaged.

                     HOPE IT HELPS!!!!!