Question

An electric oven of 2kW power rating is operated in a domestic electric circuit (220V) that has a current rating of 5A. What results do you expect? Explain.

Answer 1

Pover= voltage* current

current=2000/220 =9A

So the current exceeds the limit and the fuse will burn out. If there is no fuse then overloading will cause melting of wires which will cause shortcircuit which will cause a fire

Answer 2

Answer:

P(power)= 2kW(Given)

2kW= 2000W

V(Volt)= 220 V

Then the current drawn by electric oven is

I(CURRENT)=P/V

=2000W/220 V

=9.09 A

Explanation:

I= CURRENT

P= POWER

V= VOLT