Question

An electric oven of 3 kW power rating is operated in a domestic electric circuit that has
current rating 4A. If the supply voltage is 220 V, what result do you expect?Explain
​

Answer 1

Answer:

Power = V×I

2kW = 220 × I

I = 2000/220

I = 9.09 A

As the amount of current flowing in the conductor is more than 5 A, the fuse will get broken and hence the circuit will get open.

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Answer 2

Explanation:

Current drawn by the electric oven can be obtained by the expression,

P = VI

Where,

Current = I

Power of the oven, P = 2 kW = 2000 W

Voltage supplied, V = 220 V

I = 2000/220 V = 9.09 A

Hence, the current drawn by the electric oven is 9.09 A, which exceeds the safe limit of the circuit. Fuse element of the electric fuse will melt and break the circuit.