An electric oven of 8kw power rating is operative in a domestic electric circuit that has a current 5 complex.what result to be explain
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In this problem we have
Power of the oven (P) = 2 kW = 2000 W
Potential Difference (V) = 220 V
We have P = VI
⇒I=P/V
= 2000/220
= 9.09A
Here the current drawn by the electric oven is 9.09 A, which exceeds the safe limit of the circuit that is 5A. Therefore electric fuse will melt and break the circuit.
Power of the oven (P) = 2 kW = 2000 W
Potential Difference (V) = 220 V
We have P = VI
⇒I=P/V
= 2000/220
= 9.09A
Here the current drawn by the electric oven is 9.09 A, which exceeds the safe limit of the circuit that is 5A. Therefore electric fuse will melt and break the circuit.
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