An electric oven of resistance 40 ohm takes a current of 5 A . Calculate the heat developed in 30 seconds
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Here is ur answer........
R = 40 ohm
I = 5A
t = 30 sec.
Therefore heat,
H = ( I )^2 × R × t
H = ( 5 )^2 × 40 × 30
H = 25 × 40 × 30
H = 30,000 J
H = 30 KJ.
Hope it helps!!☺☺
R = 40 ohm
I = 5A
t = 30 sec.
Therefore heat,
H = ( I )^2 × R × t
H = ( 5 )^2 × 40 × 30
H = 25 × 40 × 30
H = 30,000 J
H = 30 KJ.
Hope it helps!!☺☺
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