Question

An electric pole is 10 m high. A steel wire tied to
the top of the pole is affixed at a point on the
ground to keep the pole upright. If the steel wire
makes an angle 45° with the horizontal through
the foot of the pole, find the length of the steel
wire. (Given V2 = 1.41)

Answer 1

Step-by-step explanation:

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Answer 2

$\large{\underline{\underline{\mathfrak{\green{\bf{Solution:-}}}}}}$.

$\large{\underline{\underline{\mathfrak{\bf{Given\:Here:-}}}}}$.

• Length of electric pole OA = 10m

• Angle $\angleB\:=\:45^{\circ}$.

Let, OA be the electric pole and B be the point on the ground ,

Let,

• BA = x cm

$\large{\underline{\underline{\mathfrac{\bf{\:In\:\:\triangle ABO:-}}}}}$

$\large\boxed{\boxed{\sin45°\:=\frac{AO}{AB}\:=\frac{perpendicular}{hypotenus}}}$

we know ,

$\large\boxed{\sin45^{\circ}\:=\frac{1}{\sqrt{2}}}$

So,

$\implies\frac{1}{\sqrt{2}}\:=\frac{10}{x}$

$\implies\:x\:=\:10×\sqrt{2}$

$\implies\:x\:=\:10×1.414$

$\implies\:x\:=\:14.14$

Hence ,

Length of wire ( AB) is = 14.14 m

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