Question

An electric pole is 10 m high. A steel wire tied to the top of the pole is affixed at a point on the ground to keep the pole upright. If the wire makes an angle of 45 with the horizontal through the foot of the pole, find the length of the wire.​

Answer 1

Step-by-step explanation:

Let AB=10= Height of Pole

and AD be the length of the wire

From △ABD

sin45

o

=

AD

AB

⇒

2

1

=

AD

10

⇒AD=10

2

⇒10×1.414 (Take

2

=1.414)

=14.14 m

Answer 2

Solution :-

Consider AB as the pole and AC as the wire which makes an angle of 450 with the ground.

Height of the pole AB = 10 m

Consider x m as the length of wire AC.

[ Refer to the attachment ]

We know that

↪sin θ = AB/AC

Substituting the values

↪sin 45° = 10/x

So we get,

↪1/√2 = 10/x

By cross multiplication

↪x = 10√2 = 10 (1.414)

↪x = 14.14m.

Hence,

• The length of the wire is 14.14 m.