Question

An electric pole is 10 m high. A stell wire tied to the top of the pole is affixed at a point on the ground to keep the upright. If tue wire makes an angel of 45° with the horizontal through the foot of the pole, find the length of the wire .​

Answer 1

$\huge\bf{Solution}$

Given :

OA = 10 m ( electric pole)

∠B = 45°

Let OA be the electric Pole and B be the point on the ground.

Let BA = x cm

In ∆ABO

sin 45° = AO /AB (perpendicular/ hypotenuse)

1 / √ 2 = 10 / x

x = 10 √2

x = 10 × 1.414 (Given √2 = 1.414)

x = 14.14 m

Hence, length of the wire is 14.14 m.