Question

an electric pole is 10m high.a steel wire tied to top of the pole is affixed at a point on the ground to keep the pole up right.if the wire makes an angel 45° with the horizontal through the foot of the pole,find the length of the wire(use √2=1.414)

Answer 1

height of pole ,p =10m

angle of elevation =45 °

line of sight ,h = ?

sin 45 ° = 1/ √2

= p/h

= h =10√2 m
h= 11.41

Answer 2

$\huge{\underline{\underline{\red{\mathbf{Answer :}}}}}$

Let OA be the electric pole and B be the point on ground to fix the pole.Let BA be x.

As per given in th question, figure is in the attachment.

So,

In ∆ ABO

$\Large{\boxed{\green{\sf{Sin \theta = \frac{Perpendicular}{Hypotenuse}}}}}$

Sin 45° = AO/AB

1/√2 = 10/x

x = 10√2

(Put √2 as 1.414)

x = 10(1.414)

x = 14.14 m

$\large{\boxed{\purple{\sf{x = 14.14 \: m}}}}$

Hence, the length of wire is 14.14 m

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