Question

An electric pole is 5m high. A steel wire tied to the top of the pole is affixed at a point on the ground to keep the pole upright. If the wire makes an angle of 60 degrees with the horizontal through the foot of the pole, find the length of the wire.​

Answer 1

Answer:

Let BA = x cm

Let BA = x cmIn ∆ABO

Let BA = x cmIn ∆ABOsin 45° = AO /AB (perpendicular/ hypotenuse)

Let BA = x cmIn ∆ABOsin 45° = AO /AB (perpendicular/ hypotenuse)1 / √ 2 = 10 / x

Let BA = x cmIn ∆ABOsin 45° = AO /AB (perpendicular/ hypotenuse)1 / √ 2 = 10 / xx = 10 √2

Let BA = x cmIn ∆ABOsin 45° = AO /AB (perpendicular/ hypotenuse)1 / √ 2 = 10 / xx = 10 √2x = 10 × 1.414 (Given √2 = 1.414)

Let BA = x cmIn ∆ABOsin 45° = AO /AB (perpendicular/ hypotenuse)1 / √ 2 = 10 / xx = 10 √2x = 10 × 1.414 (Given √2 = 1.414)x = 14.14 m

Let BA = x cmIn ∆ABOsin 45° = AO /AB (perpendicular/ hypotenuse)1 / √ 2 = 10 / xx = 10 √2x = 10 × 1.414 (Given √2 = 1.414)x = 14.14 mHence, length of the wire is 14.14 m.

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Step-by-step explanation:

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