Question

An electric power source supplies a constant current of 4 A for 6.5 s to a light bulb. The total energy given off in the form of light and heat is 2.99 kJ. Calculate the voltage drop across the bulb.​

Answer 1

The voltage drop across the bulb is 115 V.

Explanation:

Let us first calculate the total charge, which is given by below formula:

Q = I x t

As per given information:

Q = 4 x 6.5

Q = 26 C

• Now we calculate voltage drop from below formula.

Energy = Q x V

V = Energy/Q

As per given information:

V = 2.99 x 1000 / 26

V = 115 V

Thus the voltage drop across the bulb is 115 V.

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