Question

an electric pump is used to fill an overhead tank of capacity 9m3 kept at a height of 10 m above the ground if the pump takes 5 minute to fill the tank by consuming 10 kilowatt power efficiency of the pump should be :

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Answer 1

The work done to raise the water to a height of 10m equals the potential energy the water will have at 10m  

Mass of the water raised = pV = 1000kg/m^3(9m^3) = 9000kg  

PE = 9000(10)(10) = 900000 J  

Power = work/time = PE/t = 900000/300 = 3000W or 3kW  

So the efficiency = 3kW/10kW = 30%

Answer 2

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$outpot \: power = \frac{mgh}{t}$

$= \frac{9 \times {10}^{3 } \times 10 \times 10}{5 \times 60} w$

$= 3 \times {10}^{3} w$

$input \: power = 10kw$

$effeciency = \frac{3}{10} \times 100$

$= 30\%$

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