Physics, asked by priyanshi0978, 3 months ago

An electric pump of 2.5 kw is used to pump water for 5 min. Calculate the energy in joule.​

Answers

Answered by ranjitkumarboudh
0

Explanation:

Power of pump=2kW=2000W

Time(t)=60s

Height(h)=10 m

g=10ms

−2

We know,

Power=work done per unit time

Work done=mgh

=m×10×10

=100m

Power=

t

100m

2000=

60s

100m

m=1200 kg

Hence,pump can raise 1200 kg water per minute up to 10 m height

Answered by ms1699534
0

Answer:

Power of pump=2kW=2000W

Time(t)=60s

Height(h)=10 m

g=10ms

−2

We know,

Power=work done per unit time

Work done=mgh

=m×10×10

=100m

Power=

t

100m

2000=

60s

100m

m=1200 kg

Hence,pump can raise 1200 kg water per minute up to 10 m height.

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