Question

An electric pump prices 10.4 metre cube of water from a Reservoir whose water level is 4 metre below ground level to a Storage tank above ground if the discharge pipe outlet is 32 metre above the ground level and the operation takes 60 minutes find the power rating if its efficiency is 80%​

Answer 1

Answer:

Given :-

Mass, pump Flow rate = 30 kg / min. = 30 kg / 60 s. = 0.5 kg/s.

Height h = 10 m.

we know, pump water has negligible velocity , then it's K.E is zero.

Pump work to increase the level of water above 10 m.

Now weight of the water = mg

= 0.5 × 9.8

= 4.9 N.

Now power = mgh

P= 4.9 × 10 m

P= 49 W.

Now we know 1 hp = 746 W.

So minimum power = 49 / 746

=0.066

= 6.6 × 10⁻² hp.

Hence the minimum horsepower is 6.6 x 10⁻² hp.