Physics, asked by rohit3683, 11 months ago

An electric refrigerator rated 400 W operates 8 hour/day. What is
the cost of the energy to operate it for 30 days at Rs 3.00 per kWh?​

Answers

Answered by WizarD18
23

Answer:

total energy consumed in 30 days would be,

  =  > 400w \times 8.0 \times 30

 =  > 96000wh

 =  > 96kwh

thus,

the cost of energy to operate refrigerator,

96 \times 3.00

 =  > rs \:  \: 288.00

Answered by Anonymous
9

Explanation:

Power = P = 400W = 400/1000 kW = 0.4 kW

Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h

Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh

Therefore, total cost required to operate the refrigerator for the month = 96 x 30 = 2880 INR.

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