an electric refrigerator rated 400 W operates eight hours ler day. what is the cost of energy to operate if for 30 days at the Rs. 3per KWH
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Answered by
3
Answer:
Explanation:
Power of the electric refrigerator, P = 400 W = 400/1000 kW = 0.4 kW
Time for which the refrigerator operates, t = ( 30 * 8 ) hrs.
Therefore, energy consumed = P * t
= 0.4 kW * 240 h
= 96 kWh
Cost of the energy to operate refrigerator at a rate of Rs 3.00 per kWh:
= 96 * 3.00
= Rs 288.00
Hope it helps :)
Answered by
0
Answer:
i.dont no. sorry I do not help you
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