Question

an electric refrigerator rated 400 watt is used for 8 hours a day and electric iron box rated 750 watt is used for 2 hours a day calculate the cost of using these applications for 30 days if the cost of 1 kilowatt is rupees 3?​

Answer 1

hello mate

for refrigerator
convert 400 w into Kw by dividing it by thousand.
4000/1000 = .4 Kw
energy consumed in the 30days = .4 * 8 * 30 = 96 KwH

for iron
convert 750 w into Kw by dividing it by thousand.

750/1000 = 3/4 Kw

energy consumed in the 30days = 3/4 * 2 * 30 = 45 KwH

total energy consumed = 96+45 = 141

cost of 1kwh = 3rs

so 141 kwh = 3 × 141 = 423rs

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