Physics, asked by tisha9481, 1 year ago

An electric refrigerator rated 400W operates 8hours/day.what is the cost the energy to operate it for 30 days at Random. 3.00per kwh ?​

Answers

Answered by Anonymous
3

Power = P = 400W = 400/1000 kW = 0.4 kW

Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h

Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh

Therefore, total cost required to operate the refrigerator for the month = 96 x 30 = 2880 INR

Answered by geetaranipatnayak
2

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