an electric refrigerator rated 500 Watt operates 6 hours per day what is the cost of the energy to operate it for 30 days at ₹ 4.5 per KWh.
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Answered by
45
Power = 500watts = 0.5 KW
Time = 6 hrs
KWH or units consumed = 0.5 x 6
= 3 KWH
Days = 30
So units = 30 x 3
= 90 units
Cost per unit = 4.5
Total cost = 90 x 4.5
= Rs.405
Time = 6 hrs
KWH or units consumed = 0.5 x 6
= 3 KWH
Days = 30
So units = 30 x 3
= 90 units
Cost per unit = 4.5
Total cost = 90 x 4.5
= Rs.405
Answered by
8
Given - Power, usage and cost
Find - Total cost
Solution - Total time for which refrigerator operates = 30*6
Performing multiplication
Total time = 180 hours.
1000 Watts = 1 kW
So, Power in kW = 500/1000
Performing division
Power in kW = 0.5 kW
Total energy consumed = Power*time
Total energy consumed = 0.5*180
Performing multiplication
Total energy consumed = 90 kWh
Cost of energy consumption = 90*4.5
Performing multiplication
Cost of energy consumption = Rupees 405
Hence, the cost of running electric refrigerator will be Rupees 405.
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