Question

An electric refrigerator rated 500w operated 6 hours/day. What is the cost of energy to operate it 30 days at 2.45 per kwh

Answer 1

Power rating :: 500W = 500/1000= 0.5KW

operating hours perday:: 6 hours

KWH for 1 day = 0.5 KW × 6 Hours= 3KWH

for 30 days total KWH = 30×3= 90KWH

Cost for 30 days at ₹2.45 per KWH is = 90×2.45 = ₹ 220.5

MARK AS BRAINLIST ::: THANK YOU