Question

An electric refrigerator rated 500w operates 24 hr/day . what is the cost o the energy to operate it for 20 days at ₹2.00 per kWh?​

Answer 1

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⚫Energy consumed in one day = P× t

=> (0.5 kW)×(24,hr)

=> 12 kWh

⚫ Energy Consumed in 20 days

=> 20×12

=> 240 kWh

⚫Cost of energy= 240×2

=> ₹480...

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Answer 2

Power = P = 500W = 500/1000 kW = 0.5kW

Total time for which the refrigerator operated = t = 24 hours x 20 days = 480 h

Since, Energy consumed = P x t E = 0.5 x 480 kWh = 940kwh