An electric refrigerator rated 500W operates10hr/day. What is the cost of energy to operate if for 30days at Rs 2. 50 KW/h
Answers
Answered by
21
In question it should be “……for 30 days at Rs. 2.50 per kWh”
Total time taken for 30 days = 300 hours
Energy = Power × Time
= 500 W × 300 hours
= 150 kWh
Cost = 150 kWh × ₹2.50 (kWh)^-1
= ₹375
Total time taken for 30 days = 300 hours
Energy = Power × Time
= 500 W × 300 hours
= 150 kWh
Cost = 150 kWh × ₹2.50 (kWh)^-1
= ₹375
Answered by
0
Answer:
correct
Explanation:
ydytfozhgjKyUfhRxuYfyzgzc cxvzmfdfjtvdkscfjxcndMgsjfsyostzfxuxhxtZif
Similar questions