Question

An Electric refrigerator rated 600W operates 8hr/day. What is the cost of the energy to operate it for 30 days at Rs.5.00 per KW/hr?​

Answer 1

Energy of one day =Power×Time=600W×8h=4.8KWh

Energy of 30 days =4.8 KWh×30=144 KWh

So, cost of the energy =144×5=Rs.720